0=5x^2-36x+15

Solution for 0=5x^2-36x+15 equation:

0=5x^2-36x+15

We move all terms to the left:

0-(5x^2-36x+15)=0

We add all the numbers together, and all the variables

-(5x^2-36x+15)=0

We get rid of parentheses

-5x^2+36x-15=0

a = -5; b = 36; c = -15;
Δ = b2-4ac
Δ = 362-4·(-5)·(-15)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{249}}{2*-5}=\frac{-36-2\sqrt{249}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{249}}{2*-5}=\frac{-36+2\sqrt{249}}{-10}
$